Webb8 jan. 2016 · As you know, the pH of a solution is simply a measure of the concentration of hydronium ions. pH = −log([H3O+]) So, if you get one mole of hydronium ions for every one mole of hydrochloric acid, you can say that. [H3O+] = [HCl] = 0.001 M. This means that the pH of the solution will be. pH = −log(0.001) pH = 3. Answer link. WebbNow, pH = 14-pOH ⇒ pH = 14-1 ⇒ pH = 13 Therefore, the pH of 0. 1 M NaOH solution is 13. Suggest Corrections. 2. Similar questions. Q. 100 m L of 0.1 M H C l is titrated against the 0.1 M N a O H solution. What will be the p H of the solution when 100 m L …
What is the pH of 0.1 M HCL Solution? Calculate the pH of 0.1 M HCL
Webb9 juli 2014 · The hydrogen ion concentration is the same as the concentration of the acid because HCl is a strong acid and dissociates as follows: HCl -> H + + Cl− (notice the 1:1 ratio of HCl and H +) A 1M HCl solution has a pH of 0 A 0.1M HCl solution has a pH of 1 a 0.01M HCl solution has a pH of 2 This video discusses additional examples http://genchem1.chem.okstate.edu/1515F01/ProblemSet/Spring01%20Problem%20Sets/1515PS14SP01Ans.pdf pop goes your world podcast
4. 35 Acid Base Equilibria - chemrevise
WebbA titration is carried out for 25.00 mL of 0.100 M HCl (strong acid) with 0.100 M of a strong base NaOH (the titration curve is shown in Figure 14.18). Calculate the pH at these volumes of added base solution: (a) 0.00 mL (b) 12.50 mL (c) 25.00 mL (d) 37.50 mL. Solution (a) Titrant volume = 0 mL. The solution pH is due to the acid ionization of ... WebbPS14.2. Calculate the pH at the equivalence point when 25.0 mL of 0.160 M ethylamine, CH 3CH 2NH 2, is titrated with 0.120 M HBr M acid V acid = M base V base 0.120 M . V acid = 0.160 M . 25.0 mL V acid = 0.160 M . 25.0 mL 0.120 M = 33.33 mL 33.3 mL of 0.120 M HBr is needed to reach the end point moles CH 3NH 2 = 0.160 mol L (0.025 L) = 0.00400 ... Webb30 aug. 2009 · 1 mole NaOH : 1 mole HCl 0.0119 moles NaOH : 0.0119 moles HCl 0.0119 moles HCl are present in 20mL volume ? moles of HCl present in 1000mL are (0.0119 x 1000) / 20 = 0.566M HCl However, there was a dilution factor of 20 and so the molarity of the concentrated HCl is 0.566 x 20 = 11.3M The following formula can be used: shares above 10000