How many terms of ap 24 21 18 is 78
Web18 jun. 2016 · The simplest arithmetic progression satisfying the given condition is the constant progression with all $45$ terms equal to $18.$ The sum of that progression is …
How many terms of ap 24 21 18 is 78
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WebConsider the following AP24 21 18How many terms of this AP must be taken so that their sum is 78 [4 MARKS] Formula 1 MarkConcept 1 MarkApplication 2 ... Consider the … Web16 mrt. 2024 · Best answer Given A.P. 24, 21, 18,..... First term = 24 = a and common difference = – 3 = d ... (i) Let no. of terms is n. Sum of n terms = n 2 [2a + (n − 1)d] n 2 [ …
WebExample: Find the sum of the first 20 terms of the arithmetic series if a 1 = 5 and a 20 = 62. Solution: Here, a 1 = 5 and a 20 = 62 and n = 20. If we have given the first term and the … Web25 nov. 2024 · How many terms of the AP: 24,21,18 must be taken so that thier sum is 78? See answer Advertisement Brainly User First term, a = 24 common difference, d = 21-24 = -3 let the number of terms to get sum 78 is n.
Web25 nov. 2024 · How many terms of the AP: 24,21,18 must be taken so that thier sum is 78? See answer Advertisement Brainly User First term, a = 24 common difference, d = 21-24 … Web29 jan. 2024 · Best answer Here, a = 24, d = 21 – 24 = –3, Sn = 78. We need to find n. Both values of n are admissible. So, the number of terms is either 4 or 13. ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series NEET Test Series Class 12 Chapterwise MCQ Test Class 11 Chapterwise Practice Test Class 10 Chapterwise …
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Web16 mrt. 2024 · An important question from ML Aggarwal(Avichal Publication) Find the number of terms of the A.P; 24,21,18,... must be taken such that their sum is 78. Sir … chrome download free windows 8 64 bitWebHow many terms of the A.P. 24, 21, 18, … must be taken so that the sum is 78? Explain the double answer. Advertisement Remove all ads Solution A.P. is 24, 21, 18,... Sum = … chrome download free pc 32 64 bit for freeWebLet's check sum of 4 terms ⇒ a 4 = a 3 + d ⇒ a 4 = 18 + (-3) = 15 ∴ S 4 = 24 + 21 + 18 + 15 = 78. By formula, a n = a + (n - 1)d ⇒ a 5 = 24 + (5 - 1) (-3) ⇒ a 5 = 24 + 4 (-3) ⇒ a 5 = 24 - 12 = 12. a 6 = a 5 + d = 12 + (-3) = 9 a 7 = a 6 + d = 9 + (-3) = 6 a 8 = a 7 + d = 6 + (-3) = 3 a 9 = a 8 + d = 3 + (-3) = 0 a 10 = a 9 + d = 0 + (-3) = -3 chrome download free windows 11 64 bitWebHow many terms of the A.P: 24, 21, 18, ……… must be taken so that their sum is 78? Advertisement Remove all ads Solution Let the number of terms taken be n. THe given A.P is 24, 21, 18, ..... Here a = 24 and d = 21 - 24= -3 S = n 2 [ 2 a + ( n - 1) d] ⇒ 78 = n 2 [ 2 × 24 + ( n - 1) × ( - 3)] ⇒ 78 = n 2 [ 48 - 3 n + 3] => 156 = n [51 - 3n] chrome download frenchWeb4 mrt. 2024 · How many Terms of the AP 24 21 18 must be taken so that their Sum is 78 Class 10 Maths Chapter 5 Example 13Example 13 : How many terms of the AP : 24, 21, ... chrome download free windows 10 filehorseWeb20 nov. 2013 · Expert Answer a = 78, d = 71 - 78 = -7 Let n be the required no. of terms Sn = 465 [2a + (n - 1)d] = 465 n [156 + (n - 1) (-7)] = 930 7n 2 - 163n + 930 = 0 (7n - 93) (n - 10) = 0 n = or n = 10 Neglect n = as n cannot be a fraction No. of terms (n) = 10 Answered by 20 Nov, 2013, 02:39: AM Application Videos chrome download full version offlineWebHere, First term, a =3 Common difference, d=8−3= 5 an= 78 Using formula an = a+(n−1)d to find nth term of arithmetic progression, we get an= 3+(n−1)5 {we want to find value of n … chrome download full file