WebJun 10, 2024 · You get list index out of range because you use i += 1. You don't need it. You could also learn to use for -loop without range (len (...)) like for video in allVideos: title.append ( video ['snippet'] ['title'] ) publishedDate.append ( video ['snippet'] ['publishedAt'] ) If you need number in for -loop then you can use enumerate WebJul 11, 2024 · 基于DouZero定制AI实战欢乐斗地主. Contribute to tianqiraf/DouZero_For_HappyDouDiZhu development by creating an account on GitHub.
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WebDec 19, 2024 · In python, the indexing of the elements in a list starts from 0. So, the corresponding index of the elements are: red – 0. blue – 1. green – 2. pink – 3. The … WebAug 1, 2024 · An index is a value inside an iterable object, such as a list or a string. The message “list assignment index out of range” tells us that we are trying to assign an …
WebOct 5, 2012 · 1 Answer Sorted by: 3 You are setting the upper-bound of the while loop to the length of myList, which means that the final value of counter will be the length. Since lists … WebMar 14, 2016 · 3. When you are iterating over a, you are looking at the value rather than the position of that value in the list. You could use just the value like so: a = [1, 4, 9, 16, 25, 36, 49, 64, 81, 100] l= [] for val in a: if val % 2 == 0 : l.append (val) Or alternately, if you need both the position and the value then you can use the enumerate ...
WebMar 18, 2024 · The format of your call to Sequential.fit is incorrect; the first two parameters should be x and y, rather than a tuple (x, y), i.e.: history = simple_lstm_model.fit ( x_train, y_train, epochs=epochs, validation_data= (x_test, y_test), validation_steps=50 ) Share Improve this answer Follow answered Mar 18, 2024 at 10:32 dspencer 4,188 4 20 42 WebJul 14, 2024 · The “list index out of your range” problem is likely something you’ve encountered if you’ve ever worked with lists. Even though this problem occurs frequently, …
WebApr 16, 2014 · 2. When you write. for line in modo: filezise+=1. You have already consumed the file. If you want to consume it again, you need to do modo.seek (0) first to rewind the file back. If you do not rewind the file, the line below will return an empty string, because there is nothing left in the file. readit = str (modo.readline ())
WebSep 4, 2016 · You are enumerating over a string ("Chris") which means that key and value will hold the following values during the iteration: 0 "C" 1 "h" 2 "r" 3 "i" 4 "s". value [key] in the first iteration is ok, it returns 'C'. In the second iteration, the index 1 is out of range for … oak and 41stWebJan 26, 2014 · 3. For your first question: the index starts at 0, as is generally the case in Python. (Of course, this would have been very easy to try for yourself and see). >>> x = ['a', 'b', 'c'] >>> for i, word in enumerate (x): print i, word 0 a 1 b 2 c. For your second question: a much better way to handle printing every 30th line is to use the mod ... oak and 10thWebFeb 15, 2024 · Lists are indexed starting from 0, so for a list of length, say, 13, the last valid index is 12, i.e., 1 less than the length. When you do looplim=(len(x)+1) and then for i in range (0,looplim), the last value of i is looplim-1 which is equal to len(x), so it's the length rather than 1 less than that. oak and 49thWebMar 13, 2024 · Python中的“list index out of range”错误表示您正在尝试访问列表中不存在的索引位置。这可能是因为您正在尝试访问一个空列表或尝试访问超出列表范围的索引位置。 mah of duracell aaWebMar 22, 2024 · List comprehension vs. for loop performance testing. In an effort to avoid Django ModelSerialization performance hits, I am looking at "serializing" a result set on my own. Many related Stackoverflow questions say that list comprehension should be the fastest, but my own tests are showing nested for loops being consistently faster. mah of lawn mower batteryWeb这段代码是在对神经网络的后骨干网络进行遍历，对每一层进行操作。其中，使用enumerate函数对每一层进行编号，使用for循环进行遍历。在每一层中，将输入x传入该层进行计算，得到输出x。如果该层的编号在[2, 6, 13, 22]中，则进行特殊操作。 mah of iphone 12WebApr 28, 2015 · r = xrange (2000, 2005) r2 = xrange (1, len (r) + 1) h = zip (r2, r) print h. If you want to create a generator instead of a list then you can use izip instead. This answer is way out of date, you can now put just enumerate (iterable, start=1) as of Python 2.6. mah of iphone 13 pro max